If one number is 2 more than 3 times another number and their sum is 22, how can I find these numbers?

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To solve the problem, let’s define the two numbers. Let x be the first number and y be the second number.

According to the information given:

  • One number (let’s say x) is 2 more than 3 times another number (y):
    • x = 3y + 2
  • The sum of the two numbers is 22:
    • x + y = 22

Now, we can substitute the expression for x from the first equation into the second equation:

x + y = 22
(3y + 2) + y = 22

Now, simplify and combine like terms:

3y + 2 + y = 22
4y + 2 = 22

Next, subtract 2 from both sides:

4y = 20

Then, divide by 4 to solve for y:

y = 5

Now that we have the value of y, we can find x using the first equation:

x = 3y + 2
x = 3(5) + 2
x = 15 + 2
x = 17

Therefore, the two numbers are:

  • x = 17
  • y = 5

In conclusion, the two numbers we are looking for are 17 and 5.

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