To solve for x given the equations 2x2 + 8y = 1215 and x2 + 8y = 1215, we first notice that both equations share the term 8y, which allows us to manipulate the equations effectively.
1. **Isolate 8y**: From the second equation, we can isolate 8y:
x2 + 8y = 1215 can be rewritten as 8y = 1215 – x2.
2. **Substituting 8y**: Now, we substitute this expression for 8y into the first equation:
2x2 + (1215 – x2) = 1215
3. **Simplifying the equation**: Simplifying gives us:
2x2 – x2 + 1215 = 1215
or x2 = 0.
4. **Solving for x**: Since x2 = 0, we find that:
x = 0.
5. **Conclusion**: Therefore, the value of x when both equations hold true is 0.