What is the factorization of the quadratic expression 8x² + 13x + 6?

To factor the quadratic expression 8x² + 13x + 6, we follow a systematic approach:

  1. Identify the coefficients: In the expression ax² + bx + c, we have:
    • a = 8
    • b = 13
    • c = 6
  2. Multiply a and c: We calculate:
    • 8 (from a) * 6 (from c) = 48
  3. Find two numbers that multiply to 48 and add up to 13: We need two numbers whose product is 48 and sum is 13. Those numbers are:
    • 3 and 16
  4. Rewrite the middle term: Replace 13x with 3x + 16x:
    • 8x² + 3x + 16x + 6
  5. Group the terms: We will group the first two terms and the last two terms:
    • (8x² + 3x) + (16x + 6)
  6. Factor out common factors: From each group, we can factor out:
    • For the first group (8x² + 3x), factor out x: x(8x + 3)
    • For the second group (16x + 6), factor out 2: 2(8x + 3)
  7. Combine the factors: Now we can combine our factored terms:
    • x(8x + 3) + 2(8x + 3)
  8. Factor out the common binomial: Both terms have a common factor of (8x + 3):
    • (8x + 3)(x + 2)

Therefore, the factorization of the quadratic expression 8x² + 13x + 6 is:

(8x + 3)(x + 2)

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