What is the product of 4y, 32y^2, 3y, and 5?

To find the product of the terms 4y, 32y², 3y, and 5, we will multiply them together step by step.

1. First, let’s group the coefficients (the numerical parts) together and the variable parts together:

• Coefficients: 4, 32, 3, and 5
• Variables: y, y², and y

2. Now, we will multiply the coefficients:

• 4 * 32 = 128
• 128 * 3 = 384
• 384 * 5 = 1920

So the product of the coefficients is 1920.

3. Next, we will multiply the variables. When multiplying variables, we add their exponents:

• y¹ (from 4y) + y² (from 32y²) + y¹ (from 3y) = y^(1+2+1) = y⁴

4. Finally, we combine the product of the coefficients with the product of the variables:

The final product is 1920y⁴.

Thus, the product of 4y, 32y², 3y, and 5 is 1920y⁴.