What is the width of a box shaped like a rectangular prism with a height of 17 inches, a volume of 2720 cubic inches, and a length that is 4 inches greater than twice the width?

To find the width of the box, we need to use the formula for the volume of a rectangular prism, which is:

Volume = Length × Width × Height

Given:

  • Volume = 2720 in³
  • Height = 17 in
  • Length = 2w + 4 (where w is the width)

We can set up the equation:

2720 = (2w + 4) × w × 17

First, we can simplify this equation:

2720 = 17(2w + 4)w

Next, divide both sides by 17:

160 = (2w + 4)w

Expanding this gives:

160 = 2w² + 4w

Rearranging this into a standard quadratic form:

2w² + 4w – 160 = 0

Dividing the entire equation by 2:

w² + 2w – 80 = 0

Now we can use the quadratic formula to find the width:

w = (-b ± √(b² – 4ac)) / (2a)

Here, a = 1, b = 2, and c = -80. Plugging in these values:

w = (-2 ± √(2² – 4 × 1 × -80)) / (2 × 1)

w = (-2 ± √(4 + 320)) / 2

w = (-2 ± √324) / 2

w = (-2 ± 18) / 2

This gives us two potential solutions:

w = (16) / 2 = 8 or w = (-20) / 2 = -10

Since width cannot be negative, the width of the box is:

w = 8 inches

Thus, the width of the box is 8 inches.

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