To solve the equation 28y + 6 = 02y + 5y + 14, let’s first simplify both sides of the equation.
1. Simplifying the right side:
- 02y + 5y can be simplified as follows:
- 02y = 2y, so we have 2y + 5y = 7y.
This means that the equation now looks like this:
28y + 6 = 7y + 14
2. Next, we want to get all the terms involving y on one side and constant terms on the other side. We can do this by subtracting 7y from both sides:
28y – 7y + 6 = 14
This simplifies to:
21y + 6 = 14
3. Now, let’s isolate 21y by subtracting 6 from both sides:
21y = 14 – 6
So we have:
21y = 8
4. Finally, we divide both sides by 21 to solve for y:
y = 8 / 21
This fraction is already in its simplest form. Thus, the solution to the linear equation 28y + 6 = 02y + 5y + 14 is:
y = 8/21
In summary, by systematically simplifying and isolating y, we find that the value of y that satisfies the equation is 8/21.