To find the four consecutive odd integers that sum up to 216, let’s denote the first odd integer as x. The next three consecutive odd integers can then be expressed as:
- First integer: x
- Second integer: x + 2
- Third integer: x + 4
- Fourth integer: x + 6
Now, we’ll set up an equation based on their sum:
x + (x + 2) + (x + 4) + (x + 6) = 216
Simplifying the left side, we get:
4x + 12 = 216
Next, we will isolate x by subtracting 12 from both sides:
4x = 216 – 12
4x = 204
Next, divide both sides by 4:
x = 51
Now that we have the value of x, we can substitute it back to find the four consecutive odd integers:
- First integer: 51
- Second integer: 53
- Third integer: 55
- Fourth integer: 57
To confirm, let’s add them up:
51 + 53 + 55 + 57 = 216
Thus, the four consecutive odd integers are 51, 53, 55, and 57.