What is the value of the discriminant for the trinomial 3x² + 6x + 5?

To find the discriminant of the trinomial 3x² + 6x + 5, we first need to recall the formula for the discriminant, which is derived from the quadratic equation in the standard form, ax² + bx + c. The discriminant (D) is given by:

D = b² – 4ac

In this trinomial, the coefficients are:

  • a = 3
  • b = 6
  • c = 5

Now, we can plug these values into the discriminant formula:

D = (6)² – 4(3)(5)

Calculating the first part:

(6)² = 36

Now for the second part:

4(3)(5) = 60

Now, we substitute these values back into our discriminant formula:

D = 36 – 60

This simplifies to:

D = -24

Since the discriminant is negative (-24), it indicates that the trinomial 3x² + 6x + 5 has no real roots and therefore the corresponding quadratic equation does not intersect the x-axis.

In conclusion, the value of the discriminant for the given trinomial is -24.

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