Solving the System of Equations
We start with the two equations:
- Equation 1: y = x² – 5x + 4
- Equation 2: y = x² – 9x + 18
Since both equations are equal to y, we can set them equal to each other:
x² – 5x + 4 = x² – 9x + 18
Next, we can eliminate x² from both sides:
-5x + 4 = -9x + 18
Now, let’s isolate terms involving x. We can start by adding 9x to both sides:
4 = -5x + 9x + 18
This simplifies to:
4 = 4x + 18
Next, we subtract 18 from both sides:
4 – 18 = 4x
This gives us:
-14 = 4x
Now, divide both sides by 4:
x = -rac{14}{4} = -rac{7}{2}
Now that we have the value of x, we can substitute it back into either of the original equations to find y. We will use Equation 1:
y = (-rac{7}{2})² – 5(-rac{7}{2}) + 4
Calculating step by step:
- y = rac{49}{4} + rac{35}{2} + 4
- Converting 4 to a fraction: y = rac{49}{4} + rac{35}{2} + rac{16}{4}
- Now, convert rac{35}{2} to the equivalent fraction: rac{35}{2} = rac{70}{4}
- Now, we have: y = rac{49}{4} + rac{70}{4} + rac{16}{4} = rac{135}{4}
Thus, the solution to the system of equations is:
Solution:
(x, y) = igg(-rac{7}{2}, rac{135}{4}igg)