How can I solve the equation x² – 2x – 20 using the quadratic formula?

The quadratic formula is a useful tool for finding the solutions to any quadratic equation of the form ax² + bx + c = 0. The formula is:

x = (-b ± √(b² – 4ac)) / (2a)

In this case, your equation is:

x² – 2x – 20 = 0

Here, we can identify the coefficients:

  • a = 1
  • b = -2
  • c = -20

Now, plug these values into the quadratic formula:

x = (-(-2) ± √((-2)² – 4(1)(-20))) / (2(1))

First, simplify what’s under the square root:

b² – 4ac = (-2)² – 4(1)(-20) = 4 + 80 = 84

Now, substitute it back into the formula:

x = (2 ± √84) / 2

Next, simplify √84. Note that √84 = √(4 * 21) = 2√21. So we can rewrite our equation:

x = (2 ± 2√21) / 2

Now, simplify further by dividing all terms by 2:

x = 1 ± √21

Thus, we find two values for x:

  • x = 1 + √21
  • x = 1 – √21

To get numerical approximations:

  • x ≈ 5.58
  • x ≈ -3.58

So, the values of x which solve the equation x² – 2x – 20 = 0 are approximately 5.58 and -3.58.

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