To find three consecutive even integers that sum up to 30, let’s denote the first even integer as x. Since we are looking for consecutive even integers, the next two integers can be represented as x + 2 and x + 4.
Now, we can set up the equation based on the information provided:
x + (x + 2) + (x + 4) = 30
If we simplify that, we get:
3x + 6 = 30
Next, we want to isolate x. Start by subtracting 6 from both sides:
3x = 30 – 6
3x = 24
Now, divide both sides by 3:
x = 8
Now that we have the first integer, we can find the other two integers:
- First even integer: x = 8
- Second even integer: x + 2 = 10
- Third even integer: x + 4 = 12
Thus, the three consecutive even integers are 8, 10, and 12.