What are two numbers whose sum is 39, given that one number is twice as large as the other?

To solve the problem, let’s denote the two numbers as x and y.

According to the information provided, we know two things:

  • The sum of the two numbers is 39, which can be represented mathematically as:
  • x + y = 39

Additionally, it is stated that one number is twice as large as the other. Without loss of generality, let’s assume:

  • y = 2x

Now we can substitute the value of y in the first equation:

  • x + 2x = 39

This simplifies to:

  • 3x = 39

Next, we can solve for x by dividing both sides of the equation by 3:

  • x = 39 / 3
  • x = 13

Now that we have the value of x, we can find y using the equation y = 2x:

  • y = 2 * 13
  • y = 26

Thus, the two numbers are 13 and 26.

In conclusion, the numbers that satisfy the conditions of the problem are:

  • First number: 13
  • Second number: 26

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