To determine the equivalent system of the given equations, we first need to analyze the equations:
1. Equation 1: 23x + y = 2
2. Equation 2: x + 12y = 3
Next, we will solve these equations to find an equivalent system that may present the same solution set.
Step 1: Solve Equation 1 for y:
We can rearrange Equation 1 to isolate y:
y = 2 - 23x
Step 2: Substitute y in Equation 2:
Let’s substitute the expression we found for y into Equation 2:
x + 12(2 - 23x) = 3
Now, distribute 12 across the parentheses:
x + 24 - 276x = 3
This simplifies to:
-275x + 24 = 3
Now, isolate -275x:
-275x = 3 - 24
-275x = -21
Dividing both sides by -275 gives:
x = rac{21}{275}
Step 3: Solve for y:
Now substitute x back into the expression for y:
y = 2 - 23(rac{21}{275})
This can be calculated as:
y = 2 - rac{483}{275}
Finding a common denominator:
y = rac{550}{275} - rac{483}{275} = rac{67}{275}
So we have our solution set:
x = rac{21}{275}, y = rac{67}{275}
To construct an equivalent system, we can express these relationships as:
– Multiply Equation 1 by 1 (to keep it the same):23x + y - 2 = 0
– Multiply Equation 2 by 1 (to keep it the same):x + 12y - 3 = 0
Thus, the equivalent system is:
23x + y - 2 = 0
x + 12y - 3 = 0
This shows how we derived the equivalent system from the given equations.