What is the value of dy/dx when given the expression 3x^2y^2?

To determine the value of dy/dx when given the expression 3x^2y^2, we need to perform implicit differentiation, assuming there is a relationship between x and y.

First, let’s set the expression equal to a constant, say C 3x^2y^2 = C. Now we will differentiate both sides of this equation with respect to x.

Using the product rule and the chain rule, we differentiate:

1. Differentiate 3x^2 with respect to x:
6xy^2

2. Differentiate y^2 with respect to x:
Here, we apply the chain rule: 2y(dy/dx)

Combining these results, applying the product rule, we get:

3(2xy^2)(dx/dx) + 3x^2(2y(dy/dx)) = 0

Thus, our equation becomes:

6xy^2 + 6x^2y(dy/dx) = 0

Now, we can solve for dy/dx:

6x^2y(dy/dx) = -6xy^2

Dividing both sides by 6x^2y (assuming y ≠ 0 and x ≠ 0), we find:

dy/dx = -xy/y^2

Finally, the value of dy/dx depends on the specific values of x and y. If x = x1, substitute this value back into our equation to find the corresponding dy/dx at that point. Simply plug in your known values of x1 and y to obtain the numerical value of the derivative.

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