How old is Kevin now if he is 3 years older than Daniel and two years ago he was 4 times as old as Daniel?

Let’s define the ages of Kevin and Daniel:

• Let D represent Daniel’s current age.
• Since Kevin is 3 years older than Daniel, Kevin’s current age can be represented as K = D + 3.

Now, we need to analyze their ages from two years ago:

• Two years ago, Daniel’s age was D – 2.
• Two years ago, Kevin’s age was K – 2 = (D + 3) – 2 = D + 1.

According to the information given, two years ago, Kevin was 4 times as old as Daniel:

• So, the equation can be set up as follows:
• K – 2 = 4 * (D – 2)

Substituting Kevin’s age in terms of Daniel into the equation, we get:

• D + 1 = 4 * (D – 2)

Now, let’s solve the equation:

1. First, distribute 4 on the right side:
2. D + 1 = 4D – 8
3. Next, we need to get all terms involving D on one side:
4. 1 + 8 = 4D – D
5. 9 = 3D
6. Now, divide both sides by 3:
7. D = 3

Now that we have Daniel’s current age, which is 3 years, we can find Kevin’s age:

• K = D + 3 = 3 + 3 = 6

Thus, Kevin’s current age is 6 years old.