What are the solutions to the linear equations 2x + y = 1 and 3x + y = 6?

To find the solution to the system of linear equations:

  • Equation 1: 2x + y = 1
  • Equation 2: 3x + y = 6

We can solve this system using the substitution or elimination method. Here, we’ll use the elimination method:

Step 1: Align the equations

Let’s write both equations clearly:

1)  2x +  y = 1  
2)  3x +  y = 6

Step 2: Eliminate one variable

We can eliminate y by subtracting Equation 1 from Equation 2:

(3x + y) - (2x + y) = 6 - 1

Which simplifies to:

3x - 2x = 5

This results in:

x = 5

Step 3: Substitute x back into one of the original equations

Now that we have the value of x, we can substitute it back into either Equation 1 or Equation 2. Let’s use Equation 1:

2(5) + y = 1

Which simplifies to:

10 + y = 1

Solving for y gives:

y = 1 - 10
y = -9

Step 4: Write the solution

We have found the values of x and y:

The solution to the system of equations is:
(x, y) = (5, -9)

Conclusion

The solution to the equations 2x + y = 1 and 3x + y = 6 is (5, -9). This means that when x is 5, y will be -9, satisfying both equations.

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