If we have the equation 8z + 9 = 8z + 9 + a^2 + b, what is the value of a?

To find the value of a in the equation 8z + 9 = 8z + 9 + a^2 + b, we need to first simplify the equation and isolate a.

Let’s start by simplifying both sides:

  1. The left-hand side (LHS): 8z + 9
  2. The right-hand side (RHS): 8z + 9 + a^2 + b

Notice that both sides have the same expression 8z + 9. We can subtract this expression from both sides:

8z + 9 - (8z + 9) = 8z + 9 + a^2 + b - (8z + 9)

Which simplifies to:

0 = a^2 + b

This result tells us that the sum of a squared and b must equal zero. For a square term like a^2 to be zero, a must be zero itself because the square of any real number is non-negative. Therefore:

a^2 = 0

From this equation, it follows that:

a = 0

Thus, the value of a is 0. The value of b must also be 0 for the equation to hold true.

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