How do you rewrite the function f(x) = 2(x – 12)^2 + 3 from vertex form to standard form?

To convert the function f(x) = 2(x – 12)^2 + 3 from vertex form to standard form, we will follow a few simple algebraic steps.

Vertex form of a quadratic function is expressed as:

f(x) = a(x – h)^2 + k

where (h, k) is the vertex of the parabola. In this case, our vertex is (12, 3) and a = 2.

Now, let’s expand the expression:

  1. Start by expanding the squared term:
    • (x – 12)^2 expands to x^2 – 24x + 144.

Substituting this back into the function gives:

f(x) = 2(x^2 – 24x + 144) + 3

  1. Distribute the 2 across the terms in the parentheses:
    • This becomes f(x) = 2x^2 – 48x + 288 + 3.

Finally, combine like terms:

f(x) = 2x^2 – 48x + 291

So, in standard form, the quadratic function is:

f(x) = 2x^2 – 48x + 291

This standard form clearly shows the coefficient of the squared term and the linear term, which makes it easier to analyze the graph of the function.

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