Suppose A and B are independent events. Given that P(A) = 0.4 and P(B) = 0.1, what is P(A ∪ B)?

To find the probability of the union of two independent events A and B, we can use the following formula:

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

Since A and B are independent events, the probability of their intersection can be calculated as:

P(A ∩ B) = P(A) × P(B)

Now, substituting the given probabilities:

  • P(A) = 0.4
  • P(B) = 0.1

First, we calculate P(A ∩ B):

P(A ∩ B) = P(A) × P(B) = 0.4 × 0.1 = 0.04

Now, we can substitute this value back into the union formula:

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

P(A ∪ B) = 0.4 + 0.1 – 0.04

P(A ∪ B) = 0.5 – 0.04 = 0.46

Therefore, the probability of A union B, P(A ∪ B), is 0.46.

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