How do I find the vertex of the parabola given by the equation y = x² + 6x + 2?

Finding the Vertex of the Parabola

The equation of the parabola is given as:

y = x² + 6x + 2

To find the vertex of a parabola represented by a quadratic equation in the standard form y = ax² + bx + c, we can use the formula for the x-coordinate of the vertex:

x = -½ * b

In our equation, we can identify:

  • a = 1
  • b = 6
  • c = 2

Plugging the value of b into the vertex formula gives us:

x = -½ * 6 = -3

Now that we have the x-coordinate of the vertex, we need to find the corresponding y-coordinate by substituting x = -3 back into the original equation:

y = (-3)² + 6(-3) + 2

This simplifies to:

  • y = 9 – 18 + 2
  • y = -7

Thus, the vertex of the parabola is located at the point:

(-3, -7)

In conclusion, the vertex of the parabola described by the equation y = x² + 6x + 2 is:

Vertex: (-3, -7)

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