What value did Samuel overlook when calculating the difference of the given polynomials: 15x² + 11y² + 8x – 7x² – 5y² – 2x – x² – 6y² – 6x?

To find the missing value from Samuel’s solution, we need to first combine the like terms of the polynomials involved in his calculation. The polynomials given are:

15x² + 11y² + 8x – 7x² – 5y² – 2x – x² – 6y² – 6x

Now, let’s rearrange and group the similar polynomial terms:

• x² terms: 15x² – 7x² – x²
• y² terms: 11y² – 5y² – 6y²
• x terms: 8x – 2x – 6x

Now, let’s calculate each group:

1. For the x² terms:
   15x² – 7x² – x² = (15 – 7 – 1)x² = 7x²
2. For the y² terms:
   11y² – 5y² – 6y² = (11 – 5 – 6)y² = 0y²
3. For the x terms:
   8x – 2x – 6x = (8 – 2 – 6)x = 0x

Combining these results gives us:

Result: 7x² + 0y² + 0x = 7x²

Thus, the value that was missing from Samuel’s solution is:

7x²