What is the solution to the system of equations: y = x^2 – 10x + 11 and y = x^2 + x – 7?

To solve the system of equations:

1. Equation 1: y = x^2 – 10x + 11

2. Equation 2: y = x^2 + x – 7

We will set the two equations equal to one another since they both equal y:

x^2 – 10x + 11 = x^2 + x – 7

Next, we can simplify this equation by eliminating x^2 from both sides:

-10x + 11 = x – 7

Now, rearranging the equation gives us:

-10x – x = -7 – 11

Combining like terms results in:

-11x = -18

Dividing both sides by -11 yields:

x = -18 / -11 => x = 18 / 11

Now that we have the value for x, we will substitute this back into either equation to solve for y. Let’s use Equation 1:

y = (18/11)^2 – 10(18/11) + 11

Calculating this gives:

y = (324/121) – (180/11) + 11

Converting to common denominators results in:

y = (324/121) – (1800/121) + (1331/121)

Thus, combining these yields:

y = (324 – 1800 + 1331)/121 => y = (-145)/121 => y = -145 / 121

Therefore, the solution to the system of equations is: (x, y) = (18/11, -145/121).

Leave a Comment