To find the value of x at which the graphs of the equations 2x + y = 6 and 5x + 10y = 10 intersect, we need to solve the system of equations.
We have:
- Equation 1: 2x + y = 6
- Equation 2: 5x + 10y = 10
Let’s first express y from the first equation:
From Equation 1:
y = 6 - 2x
Now, substitute this expression for y into the second equation:
Substituting into Equation 2:
5x + 10(6 - 2x) = 10
Now, simplify this equation:
5x + 60 - 20x = 10
-15x + 60 = 10
-15x = 10 - 60
-15x = -50
x = rac{-50}{-15} = rac{10}{3}
So, the value of x at which the graphs of the two equations intersect is x = rac{10}{3}, or approximately 3.33.
This means that at x = rac{10}{3}, the corresponding value of y can also be found by substituting x back into one of the original equations. Let’s substitute it back into Equation 1 to find y:
y = 6 - 2(rac{10}{3}) = 6 - rac{20}{3} = rac{18}{3} - rac{20}{3} = -rac{2}{3}
Thus, the two equations intersect at the point (rac{10}{3}, -rac{2}{3}).