What is the value of x in the equation 4x + 8y = 40 when y = 8?

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To determine the value of x in the equation 4x + 8y = 40 when y = 8, we can start by substituting the value of y into the equation.

Given:

  • Equation: 4x + 8y = 40
  • Value of y: 8

Substituting y with 8:

4x + 8(8) = 40

This simplifies to:

4x + 64 = 40

Next, we isolate the term with x by subtracting 64 from both sides:

4x = 40 - 64
4x = -24

Now, to solve for x, we divide both sides by 4:

x = -24 / 4
x = -6

Thus, the value of x in the equation 4x + 8y = 40 when y = 8 is -6.

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