To solve the problem of finding the probability of rolling an odd number or a number less than 6 with a single die, we first need to identify the outcomes of a standard die roll. A standard die has six faces, numbered from 1 to 6:
- 1
- 2
- 3
- 4
- 5
- 6
Next, let’s define the two events we are interested in:
Event A: Rolling an Odd Number
The odd numbers on a die are:
- 1
- 3
- 5
So, Event A (rolling an odd number) can result in any of the three outcomes: 1, 3, or 5.
Event B: Rolling a Number Less Than 6
The numbers on a die that are less than 6 are:
- 1
- 2
- 3
- 4
- 5
Thus, Event B (rolling a number less than 6) can result in five possible outcomes: 1, 2, 3, 4, or 5.
Finding the Probability of A or B
To calculate the probability of either event A or event B occurring, we can employ the principle of inclusion-exclusion:
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
Now, let’s compute each probability:
- P(A): The probability of rolling an odd number:
There are 3 odd numbers (1, 3, 5) out of a total of 6 outcomes:
P(A) = 3/6 = 1/2
- P(B): The probability of rolling a number less than 6:
There are 5 outcomes less than 6 (1, 2, 3, 4, 5):
P(B) = 5/6
- P(A ∩ B): The probability of rolling a number that is both odd and less than 6:
The odd numbers that are also less than 6 are (1, 3, 5):
P(A ∩ B) = 3/6 = 1/2
Calculating P(A ∪ B)
We can now substitute these probabilities into our inclusion-exclusion formula:
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
P(A ∪ B) = (1/2) + (5/6) – (1/2)
Calculating step by step:
- P(A ∪ B) = (1/2) + (5/6) – (1/2)
- P(A ∪ B) = (5/6)
Finally, the probability of rolling either an odd number or a number less than 6 when rolling a single die is:
P(A ∪ B) = 5/6
In conclusion, the probability of rolling an odd number or a number less than 6 is 5/6 or approximately 0.8333, which reflects a high likelihood of achieving one of these results on a single die roll.