If the function f is defined as f(x) = 3x + 1 and f(1) is the inverse of f, what is the value of f(13)?

To find the value of f(13), we first need to evaluate the function f(x) defined as:

f(x) = 3x + 1

Now, let’s compute f(13):

f(13) = 3(13) + 1

Calculating this gives us:

f(13) = 39 + 1 = 40

Therefore, the value of f(13) is:

40

Next, since it’s stated that f(1) is the inverse of f, let’s find f(1) to understand its implications:

f(1) = 3(1) + 1 = 4

For the inverse function, we denote it as f-1. The relationship of a function and its inverse is given by:

f(f-1(x)) = x and f-1(f(x)) = x

To find the inverse function f-1(y), we start from:

y = 3x + 1

Now, solving for x:

  1. Rearranging the equation gives us: y – 1 = 3x
  2. Then, we have: x = (y – 1)/3

This means the inverse function is:

f-1(y) = (y – 1)/3

From this, we can see that f(1) = 4 clearly satisfies the relationship with the inverse. We can verify this:

f(f-1(4)) = 4

Calculating:

f( (4 – 1)/3 ) = f(1) = 4

Thus, everything is consistent. In summary, the value of f(13) is:

40

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