How can I find the 31st term of the sequence 9, 15, 21?

To find the 31st term of the given sequence (9, 15, 21), we first need to analyze the pattern of the sequence.

1. **Identify the Pattern:** Let’s look at the differences between the consecutive terms:

  • The difference between the 1st term (9) and the 2nd term (15) is 15 – 9 = 6.
  • The difference between the 2nd term (15) and the 3rd term (21) is 21 – 15 = 6.

From this, we can see that this sequence increases by 6 each time. Thus, it is an arithmetic sequence.

2. **General Formula:** For an arithmetic sequence, the nth term can be calculated using the formula:

an = a1 + (n – 1) * d

Where:

  • an is the nth term,
  • a1 is the first term (9 in this case),
  • d is the common difference (6),
  • n is the term number.

3. **Calculate the 31st Term:** Now, we can substitute the values into the formula:

a31 = 9 + (31 – 1) * 6

a31 = 9 + 30 * 6

a31 = 9 + 180

a31 = 189

So, the 31st term of the sequence is 189.

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