What are the possible values of b if the complex number is represented as x + 3bi and x² = 13?

To determine the possible values of b given the complex number x + 3bi and the equation x² = 13, let’s break it down step by step.

1. **Solve for x:** Given that x² = 13, we can find x by taking the square root of both sides. This gives us:

  • x = √13 or
  • x = -√13

2. **Substituting in the complex number:** Since we have two possible values for x, we can evaluate the corresponding complex numbers:

  • If x = √13, the complex number becomes √13 + 3bi.
  • If x = -√13, the complex number becomes -√13 + 3bi.

3. **Considering the value of b:** In this context, the value of b can be any real number. The presence of bi indicates that the complex number has an imaginary component, and b can vary to represent any point along the imaginary axis related to the real numbers defined by x.

In summary, since b is independent of the value of x, any real number would be a possible value for b. Thus, b can be any real number.

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