What are the steps to find an exponential function of the form f(x) = ab^x that has a given y-intercept (0, 2) and passes through the point (1, 25)?

To find the exponential function of the form f(x) = ab^x that passes through the given points, we need to use the y-intercept and the point we know. Here are the step-by-step instructions:

  1. Start with the general form of an exponential function: f(x) = ab^x.
  2. Given the y-intercept (0, 2), substitute x = 0 into the equation:
  3. f(0) = ab^0 implies f(0) = a = 2.

  4. Now we have our function partially defined as f(x) = 2b^x.
  5. Next, we use the second point (1, 25). Substitute x = 1 into the equation:
  6. f(1) = 2b^1 = 25.

  7. This simplifies to:
  8. 2b = 25.

  9. Now divide both sides by 2:
  10. b = 25 / 2 = 12.5.

  11. We now have the values for a and b, so the full exponential function can be written as:
  12. f(x) = 2(12.5)^x.

  13. To confirm, you can check that it passes through both points:
    • At (0, 2): f(0) = 2(12.5)^0 = 2, which matches the y-intercept.
    • At (1, 25): f(1) = 2(12.5)^1 = 25, which matches the second point.

Thus, the exponential function that meets both criteria is f(x) = 2(12.5)^x.

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