What is the equation for the nth term of the sequence 3, 12, 48, 192?

The given sequence is: 3, 12, 48, 192.

To find the equation for the nth term, we first examine how the sequence is generated. We can observe the following pattern:

  • The first term (n=1) is 3.
  • The second term (n=2) is 12, which is 3 x 4.
  • The third term (n=3) is 48, which is 12 x 4.
  • The fourth term (n=4) is 192, which is 48 x 4.

From this, we can see that each term can be expressed as:

  • an = an-1 x 4

Starting with an initial value (a1 = 3), we can express the terms of the sequence recursively:

  • a2 = 3 x 4 = 12
  • a3 = 12 x 4 = 48
  • a4 = 48 x 4 = 192

To derive a formula for the nth term explicitly, we can write:

an = a1 x 4(n-1) where a1 = 3.

Thus, substituting the value of a1, we get:

an = 3 x 4(n-1)

So, the equation for the nth term of the sequence is:

an = 3 x 4(n-1)

This formula indicates a geometric sequence where the first term is 3 and the common ratio is 4.

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