How can I express the equation x² + y² + 8x + 22y + 37 = 0 in standard form?

Rewriting the Equation in Standard Form

The given equation is:

x² + y² + 8x + 22y + 37 = 0

To express this equation in standard form, we need to reorganize the expression by completing the square for both the x and y terms.

Step 1: Group the x and y terms

First, we rearrange the equation:

x² + 8x + y² + 22y + 37 = 0

Step 2: Completing the square for x terms

For the x terms, we take:
x² + 8x

To complete the square, we take half of the coefficient of x (which is 8) and square it:
(8/2)² = 16

Now we can express the x terms as:

(x + 4)² – 16 (since we added 16 and need to subtract it to keep the equation balanced)

Step 3: Completing the square for y terms

Now, we apply the same technique to the y terms:
y² + 22y

Half of 22 is 11, and squaring it gives:
(11)² = 121

Thus, we rewrite the y terms as:

(y + 11)² – 121

Step 4: Substituting back into the equation

Substituting the completed squares back into the equation, we get:

(x + 4)² – 16 + (y + 11)² – 121 + 37 = 0

Simplifying this:

(x + 4)² + (y + 11)² – 100 = 0

Final Step: Isolating the standard form

To express the equation in standard form, we isolate the radius term on one side:

(x + 4)² + (y + 11)² = 100

This equation is now in the standard form of a circle, which is:

(x – h)² + (y – k)² = r²,

where (h, k) is the center of the circle and r is the radius.

Conclusion

Thus, the equation x² + y² + 8x + 22y + 37 = 0 in standard form is:

(x + 4)² + (y + 11)² = 100

with a center at (-4, -11) and a radius of 10.

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