How can I find a vector that has the same direction as the vector (2, 4, 2) but has a length of 6?

To find a vector that has the same direction as another vector but with a different magnitude, we follow these steps:

  1. Identify the original vector: Here, we are given the vector (2, 4, 2).
  2. Calculate the magnitude of the original vector: The magnitude (length) of a vector is calculated using the formula:
Magnitude = √(x² + y² + z²)

For our vector (2, 4, 2), the magnitude can be calculated as:

Magnitude = √(2² + 4² + 2²) = √(4 + 16 + 4) = √24 = 2√6
  1. Calculate the unit vector: To get a vector of length 1 that points in the same direction, we divide each component of the original vector by its magnitude:
Unit vector = (2, 4, 2) / (2√6) = (2/(2√6), 4/(2√6), 2/(2√6)) = (1/√6, 2/√6, 1/√6)
  1. Scale the unit vector to the desired length: To find the vector of length 6, we multiply the unit vector by 6:
New vector = 6 * (1/√6, 2/√6, 1/√6) = (6/√6, 12/√6, 6/√6) = (√6 * 6/6, 2√6 * 6/6, √6 * 6/6) = (√6, 2√6, √6)

Thus, the final vector that has the same direction as (2, 4, 2) but with a length of 6 is (√6, 2√6, √6).

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