What is the solution set for the equation 18 + 3n + 2n + 20 + 4n?

To find the solution set of the equation 18 + 3n + 2n + 20 + 4n = 0, we will first simplify the left side of the equation.

1. **Combine like terms**:

  • The terms involving n are 3n + 2n + 4n. If we add these together, we get:
  • 3n + 2n + 4n = 9n.

2. **Combine constant terms**:

  • The constant terms are 18 and 20. Adding these gives:
  • 18 + 20 = 38.

3. **Rewrite the equation**: Now, substituting these back into the equation gives us:

9n + 38 = 0

4. **Isolate n**: To solve for n, we can isolate it:

  • Subtract 38 from both sides:
  • 9n = -38
  • Now divide by 9:
  • n = - rac{38}{9}

5. **Final solution set**: Therefore, the solution set for the equation is:

  • { n = - rac{38}{9} }

This means that the only value of n that satisfies the equation is -38/9.

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