To find the slope of the tangent line to the graph of y = ln(2x)
at the point where x = 4
, we need to differentiate the function and then evaluate the derivative at that particular value of x
.
Step 1: Differentiate the function
First, let’s differentiate y = ln(2x)
. Using the chain rule, the derivative of ln(u)
where u = 2x
is given by:
dy/dx = (1/u) * (du/dx)
Now substituting for u
: u = 2x
, thus du/dx = 2
. Now we apply this:
dy/dx = (1/(2x)) * 2 = 1/x
Step 2: Evaluate the derivative at x = 4
Now we evaluate the derivative at x = 4
:
dy/dx = 1/4
Conclusion
Thus, the slope of the tangent line to the graph of y = ln(2x)
at the point where x = 4
is 1/4.