What are the solutions to the equation 3x^2 + 42x + 3 = 0? Please check all that apply: 4, 3, 3, 2, 4.

To solve the quadratic equation 3x2 + 42x + 3 = 0, we can either use the quadratic formula or factorization. In this case, it may be easier to apply the quadratic formula, which is:

x = (-b ± √(b² – 4ac)) / (2a)

For the equation given:

  • a = 3
  • b = 42
  • c = 3

Now, we can plug these values into the formula:

1. Calculate the discriminant:

b² – 4ac = 42² – 4 * 3 * 3

This simplifies to:

1764 – 36 = 1728

2. Since the discriminant is positive, we have two real solutions:

x = (-42 ± √1728) / (2 * 3)

Calculating the square root of 1728 gives us:

√1728 ≈ 41.57

This leads to the two potential solutions:

x₁ = (-42 + 41.57) / 6 ≈ -0.0717

x₂ = (-42 – 41.57) / 6 ≈ -13.595

Now, we have two solutions: x ≈ -0.0717 and x ≈ -13.595. Next, let’s check if any of the values given in the original question (4, 3, 3, 2, 4) are solutions:

None of the values 4, 3, 2 match our calculated solutions, which indicates that the given options do not solve the equation. Therefore, the final conclusion is:

No valid solutions among the options provided.

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