How can I use implicit differentiation to find dz/dx and dz/dy in the equation e^(6z) = xyz?

To find the derivatives dz/dx and dz/dy using implicit differentiation from the equation e^(6z) = xyz, we’ll follow these steps: Differentiate both sides: Start with the given equation: e^(6z) = xyz Apply implicit differentiation to both sides with respect to x and then y separately. Differentiate the left-hand side: Using the chain rule, differentiate e^(6z): … Read more

Given the equation y = 2x + 1, where both x and y are functions of t, how do you find dy/dt when dx/dt = 15 and x = 4? Also, how do you find dx/dt when dy/dt = 2 and x = 40?

To solve the problem, we will use the relationship between the variables x and y, defined by the equation y = 2x + 1. (a) Finding dy/dt when dx/dt = 15 and x = 4: We begin with the derivative of y with respect to t: y = 2x + 1 Differentiate both sides with … Read more