What is the integral of the function 1/(1+x^2)?
The integral of the function 1/(1+x2) is a classic result in calculus. To find this integral, we can denote it as follows: ∫ (1/(1+x2)) dx This integral is associated with the arctangent function. Thus, the solution is: ∫ (1/(1+x2)) dx = arctan(x) + C Where C is the constant of integration. The reason this integral … Read more