To find the value of x, we start by recalling the formula for the perimeter of a square. The perimeter (P) is calculated as:
P = 4 × side_length
In this case, we know that the perimeter of square JKL-M is 48 units. Setting this equal to our perimeter formula, we get:
48 = 4 × (x + 3)
Next, we can simplify the equation:
- Divide both sides by 4 to isolate the side_length:
48 ÷ 4 = (x + 3)
This simplifies to:
12 = x + 3
Now, we can solve for x by subtracting 3 from both sides:
- 12 – 3 = x
Thus, we find:
x = 9
In conclusion, the value of x, when the perimeter of square JKL-M is 48 units and the length of JK is x + 3, is 9.