Finding the Area of a Rhombus with One Diagonal and Perimeter
The area of a rhombus can be determined easily if you have one diagonal and the perimeter. Let’s break down the steps.
Understanding the Properties of a Rhombus
A rhombus is a type of polygon that is a quadrilateral (four sides) with all sides having equal length. Additionally, the diagonals of a rhombus intersect at right angles and bisect each other.
Step-by-Step Calculation
- 
			Identify the Known Variables:
- Let d1 be the length of one diagonal.
- Let P be the perimeter of the rhombus.
 
- 
			Calculate the Length of One Side:
The perimeter of a rhombus can be expressed as: P = 4s, where s is the length of one side. To find s, rearrange the formula: - s = P / 4
 
- 
			Using the Diagonals to Find the Area:
The area of a rhombus can be calculated using the formula: Area = (d1 * d2) / 2, where d2 is the length of the second diagonal. To find d2, you can use the relationship between the sides and the diagonals: s² = (d1/2)² + (d2/2)² This gives: P / 4 = √((d1² / 4) + (d2² / 4)) Squaring both sides: (P / 4)² = (d1² / 4) + (d2² / 4) Then, isolate d2²: d2² = (P² / 16) – (d1² / 4) Finally, take the square root to find d2: d2 = √((P² / 16) – (d1² / 4)) 
- 
			Calculate the Area:
Now that you have both d1 and d2, substitute them back into the area formula: Area = (d1 * d2) / 2 
Example Calculation
Let’s assume the following:
- One diagonal, d1 = 10 units
- Perimeter, P = 40 units
Now, calculate:
- Side: s = P / 4 = 40 / 4 = 10 units
- Find d2:
- d2 = √((P² / 16) – (d1² / 4))
- d2 = √((40² / 16) – (10² / 4)) = √((1600 / 16) – (100 / 4)) = √(100 – 25) = √75
- d2 ≈ 8.66 units
 
- Finally, calculate the area:
- Area = (d1 * d2) / 2 = (10 * 8.66) / 2 = 43.3 square units
 
That’s it! You now know how to calculate the area of a rhombus when provided one diagonal and the perimeter. Happy calculating!