How can I find an explicit formula for the nth term of the sequence 2, 8, 32, 128?

To find the explicit rule for the nth term of the sequence 2, 8, 32, 128, we first need to analyze the relationship between consecutive terms.

The given sequence is:

  • a1 = 2
  • a2 = 8
  • a3 = 32
  • a4 = 128

Next, let’s examine how each term relates to the previous one:

  • a2 = 2 × 4
  • a3 = 8 × 4
  • a4 = 32 × 4

We can see that each term is being multiplied by 4 to get the next term. To express this in another way, let’s see if we can write these terms in terms of powers of 4:

1. a1 = 2 = 2 × 40

2. a2 = 8 = 2 × 41

3. a3 = 32 = 2 × 42

4. a4 = 128 = 2 × 43

From these observations, we can deduce a pattern: the nth term can be expressed as:

an = 2 × 4(n-1)

To summarize, the explicit formula for the nth term of the given sequence is:

an = 2 × 4(n-1)

This formula allows you to calculate any term in the sequence by simply plugging in the value of n. For instance:

  • If n = 1, a1 = 2 × 4(1-1) = 2 × 40 = 2
  • If n = 2, a2 = 2 × 4(2-1) = 2 × 41 = 8
  • If n = 3, a3 = 2 × 4(3-1) = 2 × 42 = 32
  • If n = 4, a4 = 2 × 4(4-1) = 2 × 43 = 128

By utilizing this formula, you can not only identify terms in the sequence but also observe how the sequence grows exponentially as n increases.

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