To find three consecutive integers whose sum is 36, we can start by defining the first integer. Let’s denote the first integer as x. Since we are dealing with consecutive integers, the next two integers can be expressed as x + 1 and x + 2.
Now, we can set up an equation to represent their sum:
x + (x + 1) + (x + 2) = 36
This equation simplifies to:
3x + 3 = 36
Next, we can subtract 3 from both sides:
3x = 33
Now, divide both sides by 3:
x = 11
So, the first integer is 11. Thus the three consecutive integers are:
11, 12, 13
Finally, if we check the sum:
11 + 12 + 13 = 36. So, we’ve correctly identified three consecutive integers that sum to 36!