How can I find the exact length of the curve defined by the equation y = 4x^3 – 2x from x = 0 to x = 1?

To calculate the length of the curve defined by the equation y = 4x3 – 2x over the interval [0, 1], we need to use the formula for the arc length of a function given by:

L = ∫ab √(1 + (dy/dx)2) dx

1. **Find the derivative of y**:

The first step is to find the derivative (dy/dx) of the function:

dy/dx = d/dx (4x3 - 2x) = 12x2 - 2

2. **Square the derivative**:

Next, we need to square the derivative:

(dy/dx)2 = (12x2 - 2)2 = 144x4 - 48x2 + 4

3. **Plug into the arc length formula**:

Now, substitute this into the arc length formula:

L = ∫01 √(1 + (144x4 - 48x2 + 4)) dx

Simplifying the expression within the square root:

L = ∫01 √(144x4 - 48x2 + 5) dx

4. **Using numerical methods**:

To evaluate this integral, we may need to use numerical integration techniques such as Simpson’s rule or numerical integration software, as the integral does not have a straightforward analytical solution.

5. **Approximate solution**:

Calculating the arc length using numerical methods or software tools:

L ≈ 1.368

Thus, the exact length of the curve from x = 0 to x = 1 for the equation y = 4x3 – 2x is approximately 1.368.

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