How can I find the value of x in the equation 42x – 12 = 0?

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To find the value of x in the equation 42x – 12 = 0, follow these steps:

  1. Add 12 to both sides of the equation:

    2. This gives:

    42x - 12 + 12 = 0 + 12

    So the equation simplifies to:

    42x = 12
  2. Divide both sides by 42:

    3. This allows us to isolate x:

    x = 12 / 42
  3. Simplify the fraction:

    4. We can simplify 12/42 by dividing both the numerator and the denominator by 6:

    x = (12 / 6) / (42 / 6) = 2 / 7

So, the value of x in the equation 42x – 12 = 0 is:

x = 2/7

In conclusion, we systematically moved towards isolating x through basic algebraic operations, resulting in a simple fractional value that encapsulates the solution.

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