How can I graph the equation 15x + 5y = 30?

To graph the equation 15x + 5y = 30, we can start by rearranging it into a more familiar form, such as the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

First, let’s isolate y:

5y = -15x + 30
	y = -3x + 6

Now the equation is in slope-intercept form. We can see that:

  • The slope (m) is -3.
  • The y-intercept (b) is 6, which means the line crosses the y-axis at (0, 6).

Next, we can use the slope to find another point on the graph. Starting from the y-intercept (0, 6), we can apply the slope:

  • From (0, 6), and using a slope of -3, we move down 3 units and right 1 unit to arrive at the point (1, 3).

Now we have two points: (0, 6) and (1, 3). We can plot these points on our graph:

  • Plot the point (0, 6) on the y-axis.
  • Plot the point (1, 3).

Next, we can draw a straight line through these points. The line should extend in both directions, and it represents the equation 15x + 5y = 30.

For additional points, you can also substitute values for x to find corresponding y values. For instance:

  • If x = 2, then:
  • y = -3(2) + 6 = 0
  • So, the point (2, 0) is also on the line.

Continuing this way, you can find more points, but typically plotting two or three is sufficient to get a clear idea of the line’s direction.

In summary, by rearranging the equation, plotting points using the slope, and drawing a line through them, you’ve successfully graphed the original equation 15x + 5y = 30.

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