How can I use implicit differentiation to find dz/dx and dz/dy in the equation e^(6z) = xyz?

To find the derivatives dz/dx and dz/dy using implicit differentiation from the equation e^(6z) = xyz, we’ll follow these steps:

  1. Differentiate both sides: Start with the given equation:
  2. e^(6z) = xyz

  3. Apply implicit differentiation to both sides with respect to x and then y separately.
  4. Differentiate the left-hand side:
  5. Using the chain rule, differentiate e^(6z):

    d/dx(e^(6z)) = e^(6z) * (6 * dz/dx)
  6. Differentiate the right-hand side:
  7. Now differentiate xyz:

    d/dx(xyz) = yz + x(dy/dx)z + xy(dz/dx)
  8. Set the derivatives equal:
  9. So, we have:

    e^(6z) * (6 * dz/dx) = yz + x(dy/dx)z + xy(dz/dx)
  10. Isolate dz/dx:
  11. Now, isolate dz/dx:

    dz/dx(e^(6z) * 6 - xy) = yz + x(dy/dx)z

  12. Final formula: Thus:
  13. dz/dx = (yz + x(dy/dx)z)/(e^(6z) * 6 - xy)

This provides you with dz/dx. Next, you can repeat the process for dz/dy:

  1. Follow similar steps which include differentiating the original equation implicitly with respect to y.
  2. This will yield:
  3. dz/dy = (xz + y(dx/dy)x)/(e^(6z) * 6 - xy)

Hence, dz/dx and dz/dy can be computed using implicit differentiation on the equation e^(6z) = xyz.

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