How can we determine if the geometric series 10, 8, 64, 512 is convergent or divergent, and if it is convergent, what is its sum?

To determine if the given geometric series is convergent or divergent, we first need to identify the common ratio of the series. The series provided is: 10, 8, 64, 512.

A geometric series has a common ratio r that is found by dividing any term by the previous term. Let’s calculate the common ratio:

  • From 10 to 8: r = 8 / 10 = 0.8
  • From 8 to 64: r = 64 / 8 = 8
  • From 64 to 512: r = 512 / 64 = 8

As we can see, the common ratio changes from the first pair (0.8) to the next pairs (8), which indicates that we do not have a consistent common ratio throughout. For a series to be geometric, the ratio must be constant across all terms.

In a geometric series, if the absolute value of the common ratio, |r|, is greater than or equal to 1, the series is divergent. If |r| is less than 1, it is convergent. Since the ratios vary significantly and do not conform to the properties of a geometric series, we can conclude:

This series is not strictly a geometric series and cannot be classified as convergent or divergent in the traditional sense. Therefore, we cannot find a sum for it as we would for a proper geometric series.

If we were examining a geometric series, for instance, if it were 10, 10, 10, 10… (which has a common ratio of 1), we would state that it is divergent. If it were 10, 5, 2.5… (with a common ratio of 0.5), then it would converge, and we could compute the sum using the formula:

  • Sum S = a / (1 – r), where a is the first term and r is the common ratio.

In summary, the series provided does not fit the definition of a geometric series sufficiently to determine convergence or divergence, nor can we compute a meaningful sum.

Leave a Comment