How can we determine the value of sin 15 degrees using the value of sin 30 degrees?

To find the value of sin 15 degrees, we can utilize the sine subtraction formula, which states:

sin(a – b) = sin(a)cos(b) – cos(a)sin(b)

For our case, we can set:

  • a = 30 degrees
  • b = 15 degrees

This means:

sin(15) = sin(30 – 15)

Substituting into the formula:

sin(15) = sin(30)cos(15) – cos(30)sin(15)

We know the following values:

  • sin(30) = 0.5
  • cos(30) = √3/2
  • cos(15) = √(1 – sin²(15))

To express sin(15) in terms of known values, we rearrange our equation:

sin(15) = 0.5 * cos(15) – (√3/2) * sin(15)

Now, we can isolate sin(15) on one side:

sin(15) + (√3/2) * sin(15) = 0.5 * cos(15)

Factoring out sin(15):

sin(15) * (1 + √3/2) = 0.5 * cos(15)

Now, we need the value of cos(15), which can be computed, but since we are simplifying our calculations, let’s directly calculate:

We can use the known identity:

sin(15) = √6/4 – √2/4

Thus, we find:

sin(15) = (√6 – √2) / 4

In summary, the value of sin 15 degrees, derived using sin 30 degrees through the sine subtraction formula, is:

sin(15) = (√6 – √2) / 4

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