How can we express sin(1/x) * cos(1/y) solely in terms of x and y?

To express the expression sin(1/x) * cos(1/y) in terms of x and y only, we need to utilize some basic transformations and mathematical concepts related to trigonometric functions.

1. **Understanding the Terms**: The function sin(1/x) represents the sine of the angle 1/x, and cos(1/y) represents the cosine of the angle 1/y.

2. **Using Taylor Series Expansions**: We can approximate sine and cosine using their Taylor series expansions around zero:

  • sin(z) ≈ z - z3/6 + z5/120...
  • cos(z) ≈ 1 - z2/2 + z4/24...

3. **Substituting the Variables**: We substitute z = 1/x for sine and z = 1/y for cosine:

  • For sin(1/x), substituting gives us:
  • sin(1/x) ≈ (1/x) - (1/x)3/6 + (1/x)5/120...

  • For cos(1/y), substituting gives us:
  • cos(1/y) ≈ 1 - (1/y)2/2 + (1/y)4/24...

4. **Combining the Expressions**: Now let’s multiply the approximated sine and cosine terms together:

sin(1/x) * cos(1/y) ≈ igg[igg( rac{1}{x} - rac{1}{6x^3} + rac{1}{120x^5}igg) igg]igg[1 - rac{1}{2y^2} + rac{1}{24y^4}igg]

5. **Final Form**: The combined expression can be simplified further, resulting in a polynomial expression in terms of x and y.

In conclusion, expressing sin(1/x) * cos(1/y) in terms of x and y involves some approximation techniques with trigonometric functions. While this does not yield an exact closed form strictly in x and y, it allows us to represent the expression through approximated series. Each term gets very small as x and y increase, thus indicating that for practical computations, using the series form is often sufficient.

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