Solving the System of Equations
To solve the system of equations:
- Equation 1: x² + y = 3
- Equation 2: x + y = 3
we can use substitution or elimination methods. Here, we will use substitution for simplicity.
Step 1: Solve Equation 2 for y
From Equation 2, we can express y in terms of x:
y = 3 - x
Step 2: Substitute y in Equation 1
Now, substitute this expression for y into Equation 1:
x² + (3 - x) = 3
Now, simplify the equation:
x² + 3 - x = 3
x² - x + 3 - 3 = 0
x² - x = 0
Step 3: Factor the equation
Factor the left-hand side:
x(x - 1) = 0
Setting each factor to zero gives us:
- x = 0
- x = 1
Step 4: Solve for y using the x values
Now, substitute these x values back into Equation 2 to find the corresponding y values:
When x = 0:
y = 3 - 0 = 3
When x = 1:
y = 3 - 1 = 2
Step 5: Present the solutions
The solutions to the system of equations are:
- Solution 1: (0, 3)
- Solution 2: (1, 2)
Conclusion
Therefore, the system of equations x² + y = 3 and x + y = 3 has two solutions: (0, 3) and (1, 2).