How can you express the area of a rectangle as a function of its width if the width is twice its length?

To express the area A of a rectangle as a function of the width w, given that the width is twice the length, we start with some basic definitions.

Let the length of the rectangle be denoted as l and the width as w. According to the problem statement, the width is twice the length, which we can write mathematically as:

w = 2l

Now, we know that the area A of a rectangle is calculated by the formula:

A = length × width

Substituting the expression for the width in terms of length into the area formula gives us:

A = l × w

Since w = 2l, we can replace l in the equation:

A = l × (2l) = 2l^2

Now we need to express everything in terms of the width w. We know from the relationship w = 2l that:

l = w/2

Now, substituting this back into our area equation:

A = 2(w/2)^2

This simplifies to:

A = 2(1/4)w^2 = (1/2)w^2

Thus, we can now express the area of the rectangle as a function of the width:

A(w) = (1/2)w^2

In summary, if the width of the rectangle is twice its length, the area as a function of the width is (1/2)w^2.

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